An unmanned airplane has the capacity to carry a 50lb payload. Which of the following behaviors most likely results in the airplane malfunctioning while carrying the 50lb payload?
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The correct answer is:
The center of gravity location and limits vary for every aircraft. Each aircraft’s Pilot`s Operating Handbook or UAS Flight Manual will indicate how far from the datum and how heavy you can place a payload and still operate safely. These limits are called “the envelope”. Placing too heavy of a weight outside of the envelope range can cause the aircraft to malfunction as the aircraft was not designed to handle such loading configuration. The aircraft would be pull down from one of its sides.
That's correct! Good job
The center of gravity location and limits vary for every aircraft. Each aircraft’s Pilot`s Operating Handbook or UAS Flight Manual will indicate how far from the datum and how heavy you can place a payload and still operate safely. These limits are called “the envelope”. Placing too heavy of a weight outside of the envelope range can cause the aircraft to malfunction as the aircraft was not designed to handle such loading configuration. The aircraft would be pull down from one of its sides.
What action could result in stalling a fixed-wing aircraft?
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The correct answer is:
Stall is an event when an airplane loses a lot of lift, causing the airplane to nose dive to the ground. Stall has nothing to do with “engine stall” like you would see in a car. Stall is not about the airplane engine failing.
In aviation, stall occurs when the airplane’s angle of attack is higher than the critical angle of attack allowed. Because the angle of attack is too high, the airflow is unable to push the airplane wings upwards (lift) as the airflow path detaches itself from the wings and goes elsewhere instead.
That's correct! Good job
Stall is an event when an airplane loses a lot of lift, causing the airplane to nose dive to the ground. Stall has nothing to do with “engine stall” like you would see in a car. Stall is not about the airplane engine failing.
In aviation, stall occurs when the airplane’s angle of attack is higher than the critical angle of attack allowed. Because the angle of attack is too high, the airflow is unable to push the airplane wings upwards (lift) as the airflow path detaches itself from the wings and goes elsewhere instead.
(Refer to FAA-CT-8080-2H, Figure 1.) Angle A in this figure represents
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The correct answer is:
The angle of attack is the angle from the relative wind to the airfoil chord line. The higher the angle, the more lift you can get. There’s a maximum angle of attack you can create called the critical angle of attack. Any angle higher than the critical angle of attack will result in your aircraft stalling (sudden loss of lift and therefore dive straight to the ground).
That's correct! Good job
The angle of attack is the angle from the relative wind to the airfoil chord line. The higher the angle, the more lift you can get. There’s a maximum angle of attack you can create called the critical angle of attack. Any angle higher than the critical angle of attack will result in your aircraft stalling (sudden loss of lift and therefore dive straight to the ground).
(Refer to FAA-CT-8080-2H, Figure 2.) If an unmanned airplane weighs 45 pounds, what approximate weight would the airplane’s body be required to support during a 65° banked turn while maintaining altitude?
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The correct answer is:
Recall the gravity force an aircraft’s body endures during rolling (bank) or pitching is amplified vs. the gravity force it would endure during normal level flight. We can calculate this new force by multiplying the weight of the aircraft by its corresponding load factor.
If we refer to the graph in Figure 2 of the FAA-CT-8080-2H handbook, we see that the load factor is approximately 2.5 G’s when the bank angle is 65°.
Now, we can calculate the total force endured by the aircraft while it’s rolling at at a 65° angle.
2.5 x 45lb = 112.5lb
That's correct! Good job
Recall the gravity force an aircraft’s body endures during rolling (bank) or pitching is amplified vs. the gravity force it would endure during normal level flight. We can calculate this new force by multiplying the weight of the aircraft by its corresponding load factor.
If we refer to the graph in Figure 2 of the FAA-CT-8080-2H handbook, we see that the load factor is approximately 2.5 G’s when the bank angle is 65°.
Now, we can calculate the total force endured by the aircraft while it’s rolling at at a 65° angle.
2.5 x 45lb = 112.5lb
(Refer to FAA-CT-8080-2H, Figure 2.) A 200lb unmanned airplane drone is flying at a bank of 30° while carrying an 8lb camera that is placed 12 inches from its nose datum. What is the moment created by the airplane’s camera payload?
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The correct answer is:
Figure 2 of the FAA-CT-8080-2H book has nothing to do with solving this problem. The real Part 107 test will often include irrelevant information, like we did by talking about flying at a bank of 30°, to make you second-guess yourself when answering a question.
Now, onto the actual problem solution.
The equation for moment is
Weight X Arm distance
The arm distance (in inches) refers how far the weight is from the aircraft’s datum location. The datum location is provided by the airplane’s manufacturer. We were told the 10lb camera is 12 inches from the nose datum. Therefore,
Moment = 8lb x 12in = 96lb-inch
That's correct! Good job
Figure 2 of the FAA-CT-8080-2H book has nothing to do with solving this problem. The real Part 107 test will often include irrelevant information, like we did by talking about flying at a bank of 30°, to make you second-guess yourself when answering a question.
Now, onto the actual problem solution.
The equation for moment is
Weight X Arm distance
The arm distance (in inches) refers how far the weight is from the aircraft’s datum location. The datum location is provided by the airplane’s manufacturer. We were told the 10lb camera is 12 inches from the nose datum. Therefore,
Moment = 8lb x 12in = 96lb-inch